亚洲AV伊人久久青青草原,久久人人爽人人爽人人片AV高清 ,久久精品国产一区二区

Geometric Transformations of Images

https://docs.opencv.org/3.0-beta/doc/py_tutorials/py_imgproc/py_geometric_transformations/py_geometric_transformations.html

Goals

Learn to apply different geometric transformation to images like translation, rotation, affine transformation etc.
You will see these functions: cv2.getPerspectiveTransform

Transformations

OpenCV provides two transformation functions, cv2.warpAffine and cv2.warpPerspective, with which you can have all kinds of transformations. cv2.warpAffine takes a 2x3 transformation matrix while cv2.warpPerspective takes a 3x3 transformation matrix as input.

Scaling

Scaling is just resizing of the image. OpenCV comes with a function cv2.resize() for this purpose. The size of the image can be specified manually, or you can specify the scaling factor. Different interpolation methods are used. Preferable interpolation methods are cv2.INTER_AREA for shrinking and cv2.INTER_CUBIC (slow) & cv2.INTER_LINEAR for zooming. By default, interpolation method used is cv2.INTER_LINEAR for all resizing purposes. You can resize an input image either of following methods:

import cv2 import numpy as np  img = cv2.imread('messi5.jpg')  res = cv2.resize(img,None,fx=2, fy=2, interpolation = cv2.INTER_CUBIC)  #OR  height, width = img.shape[:2] res = cv2.resize(img,(2*width, 2*height), interpolation = cv2.INTER_CUBIC)

Translation

Translation is the shifting of object’s location. If you know the shift in (x,y) direction, let it be $(t_x,t_y)$ , you can create the transformation matrix $\textbf{M}$ as follows:

$M = \begin{bmatrix} 1 & 0 & t_x \\ 0 & 1 & t_y \end{bmatrix}$

You can take make it into a Numpy array of type np.float32 and pass it into cv2.warpAffine() function. See below example for a shift of (100,50):

import cv2 import numpy as np  img = cv2.imread('messi5.jpg',0) rows,cols = img.shape  M = np.float32([[1,0,100],[0,1,50]]) dst = cv2.warpAffine(img,M,(cols,rows))  cv2.imshow('img',dst) cv2.waitKey(0) cv2.destroyAllWindows()

Warning

Third argument of the cv2.warpAffine() function is the size of the output image, which should be in the form of (width, height). Remember width = number of columns, and height = number of rows.

See the result below:

Rotation

Rotation of an image for an angle $\theta$ is achieved by the transformation matrix of the form

$M = \begin{bmatrix} cos\theta & -sin\theta \\ sin\theta & cos\theta \end{bmatrix}$

But OpenCV provides scaled rotation with adjustable center of rotation so that you can rotate at any location you prefer. Modified transformation matrix is given by

$\begin{bmatrix} \alpha & \beta & (1- \alpha ) \cdot center.x - \beta \cdot center.y \\ - \beta & \alpha & \beta \cdot center.x + (1- \alpha ) \cdot center.y \end{bmatrix}$

where:

$\begin{array}{l} \alpha = scale \cdot \cos \theta , \\ \beta = scale \cdot \sin \theta \end{array}$

To find this transformation matrix, OpenCV provides a function, cv2.getRotationMatrix2D. Check below example which rotates the image by 90 degree with respect to center without any scaling.

img = cv2.imread('messi5.jpg',0) rows,cols = img.shape  M = cv2.getRotationMatrix2D((cols/2,rows/2),90,1) dst = cv2.warpAffine(img,M,(cols,rows))

See the result:

Affine Transformation

In affine transformation, all parallel lines in the original image will still be parallel in the output image. To find the transformation matrix, we need three points from input image and their corresponding locations in output image. Then cv2.getAffineTransform will create a 2x3 matrix which is to be passed to cv2.warpAffine.

Check below example, and also look at the points I selected (which are marked in Green color):

img = cv2.imread('drawing.png') rows,cols,ch = img.shape  pts1 = np.float32([[50,50],[200,50],[50,200]]) pts2 = np.float32([[10,100],[200,50],[100,250]])  M = cv2.getAffineTransform(pts1,pts2)  dst = cv2.warpAffine(img,M,(cols,rows))  plt.subplot(121),plt.imshow(img),plt.title('Input') plt.subplot(122),plt.imshow(dst),plt.title('Output') plt.show()

See the result:

Perspective Transformation

For perspective transformation, you need a 3x3 transformation matrix. Straight lines will remain straight even after the transformation. To find this transformation matrix, you need 4 points on the input image and corresponding points on the output image. Among these 4 points, 3 of them should not be collinear. Then transformation matrix can be found by the function cv2.getPerspectiveTransform. Then apply cv2.warpPerspective with this 3x3 transformation matrix.

See the code below:

img = cv2.imread('sudokusmall.png') rows,cols,ch = img.shape  pts1 = np.float32([[56,65],[368,52],[28,387],[389,390]]) pts2 = np.float32([[0,0],[300,0],[0,300],[300,300]])  M = cv2.getPerspectiveTransform(pts1,pts2)  dst = cv2.warpPerspective(img,M,(300,300))  plt.subplot(121),plt.imshow(img),plt.title('Input') plt.subplot(122),plt.imshow(dst),plt.title('Output') plt.show()

Result:

Additional Resources

“Computer Vision: Algorithms and Applications”, Richard Szeliski

Exercises

Help and Feedback

You did not find what you were looking for?

Ask a question on the Q&A forum.
If you think something is missing or wrong in the documentation, please file a bug report.

posted on 2017-10-12 15:28 zmj 閱讀(743) 評論(0) 編輯收藏引用

只有注冊用戶登錄后才能發(fā)表評論。
【推薦】100%開源！大型工業(yè)跨平臺軟件C++源碼提供，建模，組態(tài)！



網(wǎng)站導航: 博客園 IT新聞 BlogJava 博問 Chat2DB 管理

導航

統(tǒng)計

常用鏈接

留言簿(27)

隨筆檔案(150)

文章檔案(1)

博客鏈接

搜索

積分與排名

最新評論