Posted on 2010-08-08 22:18
MiYu 閱讀(1165)
評論(4) 編輯 收藏 引用 所屬分類:
ACM ( 模擬 ) 、
ACM ( 水題 )
MiYu原創(chuàng), 轉(zhuǎn)帖請注明 : 轉(zhuǎn)載自 ______________白白の屋
題目地址:
http://acm.hdu.edu.cn/showproblem.php?pid=1228題目描述:
Problem Description
讀入兩個小于100的正整數(shù)A和B,計算A+B.
需要注意的是:A和B的每一位數(shù)字由對應(yīng)的英文單詞給出.
Input
測試輸入包含若干測試用例,每個測試用例占一行,格式為"A + B =",相鄰兩字符串有一個空格間隔.當(dāng)A和B同時為0時輸入結(jié)束,相應(yīng)的結(jié)果不要輸出.
Output
對每個測試用例輸出1行,即A+B的值.
Sample Input
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
Sample Output
3
90
96
簡單的模擬題, 沒什么技巧
代碼如下:
MiYu原創(chuàng), 轉(zhuǎn)帖請注明 : 轉(zhuǎn)載自 ______________白白の屋
#include <iostream>
#include <map>
using namespace std;
map < string, int > mp;
void setMap ()
{
mp["one"] = 1; mp["two"] = 2; mp["three"] = 3;
mp["four"] = 4; mp["five"] = 5; mp["six"] = 6;
mp["seven"] = 7; mp["eight"] = 8; mp["nine"] = 9;
mp["zero"] = 0;
}
int main ()
{
setMap ();
string a , b, c;
while ( cin >> a )
{
cin >> b;
int sum1 = mp[a];
while ( b != "+" )
{
sum1 = sum1 * 10 + mp[b];
cin >> b;
}
cin >> b;
int sum2 = mp[b];
cin >> b;
while ( b != "=" )
{
sum2 = sum2 * 10 + mp[b];
cin >> b;
}
if ( sum1 + sum2 == 0 )
{
break;
}
cout << sum1 + sum2 << endl;
}
return 0;
}