/******************************************
設(shè)需要n年
設(shè)半圓面積為 S,半徑為 r
S = 50 * n;
S = (PI * r * r) / 2;
解得 n = (PI * r * r ) / 100;
所給點到原點距離 len = sqrt( x * x + y * y );
令len = r即可解出 n
*******************************************/
#include <iostream>
#include <cstdio>
#include <cmath>
const double PI = 3.1415927;
using namespace std;
int main()
{
double x, y;
int cnt;
cin >> cnt;
int pro = 1;
while( cnt-- )
{
cin >> x >> y;
double len = sqrt( x * x + y * y );
int n = (PI * len * len ) / (100 * 1.0);
printf("Property %d: This property will begin eroding in year %d.\n", pro++, n + 1);
}
cout << "END OF OUTPUT.\n";
return 0;
}




