| C++ |
Accepted |
|
0.031 |
197 KB |
1060. Flip Game
Time Limit: 2.0 second
Memory Limit: 16 MB
Flip game is played on a rectangular 4×4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white and vice versa. The pieces to be flipped are chosen every round according to the following rules:
- Choose any one of the 16 pieces.
- Flip the chosen piece and also all adjacent pieces to the left, to the right, to the top, and to the bottom of the chosen piece (if there are any).
Consider the following position as an example:
Here "b" denotes pieces lying their black side up and "w" denotes pieces lying their white side up. If we choose to flip the 1st piece from the 3rd row (this choice is shown at the picture), then the field will become:
The goal of the game is to flip either all pieces white side up or all pieces black side up. You are to write a program that will search for the minimum number of rounds needed to achieve this goal.
Input
The input consists of 4 lines with 4 characters "w" or "b" each that denote game field position.
Output
Write to the output a single integer number — the minimum number of rounds needed to achieve the goal of the game from the given position. If the goal is initially achieved, then write 0. If it's impossible to achieve the goal, then write the word "Impossible" (without quotes).
Sample
| input |
output |
bwbw
wwww
bbwb
bwwb
|
Impossible
|
Problem Source: 2000-2001 ACM Northeastern European Regional Programming Contest
wa了幾次
原因：1是cnt只增沒(méi)減
2是search的推出條件寫(xiě)成if(m==16){ ……}，這種情況下對(duì)于只改變最后一個(gè)即可得情況沒(méi)有判定。改成m>16
#include<iostream>
using namespace std;
bool status[6][6]={0};
const int MAX=0x7fffffff;
int cnt=0,cntMin=MAX;
bool check()
{
bool f=status[1][1];
int i,j;
for(i=1; i<=4; i++)
for(j=1; j<=4; j++)
if(f!=status[i][j])return false;
return true;
}
void turn(int i, int j)
{
status[i][j]=!status[i][j];
status[i-1][j]=!status[i-1][j];
status[i+1][j]=!status[i+1][j];
status[i][j-1]=!status[i][j-1];
status[i][j+1]=!status[i][j+1];
}
void input()
{
char ch;
for(int i=1; i<=4; i++)
for(int j=1; j<=4; j++)
{
cin>>ch;
status[i][j]=(ch=='b' ? 0 : 1 );
}
}
void search(int m)
{
if(m>16){
if( check() && (cnt<cntMin) )cntMin=cnt;
return ;
}
int i=(m+3)/4;
int j=m-4*(i-1);
turn(i,j); cnt++;
search(m+1);
turn(i,j);cnt--;
search(m+1);
}
int main()
{
input();
search(1);
if(cntMin==MAX)cout<<"Impossible"<<endl;
else cout<<cntMin<<endl;
system("pause");
return 0;
}