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C++ Jounior

once setback,once inspiration,once self-awareness
重要的是這個磨練過程，而不是結果，要的是你粗壯的腿，而不是你身上背的那袋鹽巴

求得含有最多連續特定字符個數的字符串

int ?GetMaxCountofContinuousLetter( char ? * ?p, char ?searchChar)

{

???? int ?maxCount? = 0 ;

???? int ?currentCount? = ? 0 ;

???? while ( 1 )

???? {

???????? if ( * p? == ?searchChar)

???????? {

????????????currentCount? = ? 0 ;

???????????? while ( * p? && ? * p? == ?searchChar)

???????????? {

????????????????currentCount? ++ ;

????????????????p ++ ;

????????????}

???????????? if (maxCount? < ?currentCount)

????????????????maxCount? = ?currentCount;

????????}

???????? if ( * p? == ? ' \0 ' )?

???????????? break ;

???????? else

????????????p ++ ;

????}

???? return ?maxCount;

}

int ?main()?????

{??

???? char ? * p[ 3 ] =

???? {

???????? " String(1)8818882348888856788888888988888888880 " ,

???????? " String(2)881888234888885678888888898888888880 " ,

???????? " String(3)8818882348888856788888888988888888888888880 "

????} ;

???? int ?location? = ? 0 ;

???? char ?searchChar? = ? ' 8 ' ;

???? int ?tempCount? = ? 0 ;

???? int ?maxCount? = ? 0 ;

???? for ( int ?i? = ? 0 ;i < sizeof (p) / sizeof ( * p);i ++ )

???? {

????????tempCount? = ?GetMaxCountofContinuousLetter(p[i],searchChar);

???????? if (?tempCount? > ?maxCount)

???????? {

????????????maxCount? = ?tempCount;

????????????location? = ?i;

????????}

????}

????cout << " the?string?of?maxCount?is?:? " << p[location] << endl;

????cout << " the?count?of??the?continuous?letters?is?:? " << maxCount << endl;

????cin. get ();

}

posted on 2008-04-02 09:30 snowball 閱讀(313) 評論(0) 編輯收藏引用所屬分類: 算法＋數據結構

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C++ Jounior

求得含有最多連續特定字符個數的字符串

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