欧美日韩国产一区二区三区,另类成人小视频在线,国产精品午夜电影

ACM PKU 3061 Subsequence

http://acm.pku.edu.cn/JudgeOnline/problem?id=3061

Subsequence Time Limit:1000MS  Memory Limit:65536K
Total Submit:2626 Accepted:833
Description A sequence of N positive integers (10 < N < 100 000), each of them less than or equal 10000, and a positive integer S (S < 100 000 000) are given. Write a program to find the minimal length of the subsequence of consecutive elements of the sequence, the sum of which is greater than or equal to S.
Input
The first line is the number of test cases. For each test case the program has to read the numbers N and S, separated by an interval, from the first line. The numbers of the sequence are given in the second line of the test case, separated by intervals. The input will finish with the end of file.
Output
For each the case the program has to print the result on separate line of the output file.if no answer, print 0.
Sample Input
210 155 1 3 5 10 7 4 9 2 85 111 2 3 4 5

Sample Output
23

Source
Southeastern Europe 2006

不知道為什么這道題在Discuss里被罵得體無完膚
http://acm.pku.edu.cn/JudgeOnline/bbs?problem_id=3061

注意細節很重要啊!我至少調試了兩個小時才AC!!

Source Problem Id:3061  User Id:lnmm Memory:464K  Time:31MS
Language:C++  Result:Accepted
Source

#include"stdio.h"
2

int a[100010];
3

void main()
4

{
5

long sum,N,S,min;
6

long left,right,r; //left 左游標，right 右游標, r向右擴展游標
7

int T,i;
8

scanf("%d",&T);
9

for(i=1;i<=T;i++)
10

{
11

sum=0;
12

scanf("%ld%ld",&N,&S);
13

for(r=1;r<=N;r++)
14

{
15

scanf("%ld",&a[r]);
16

sum+=a[r];
17

}
18

min=100001;
19

if(sum<S)
20

{
21

min=0;
22

}
23

sum=0;
24

right=0;
25

a[0]=0;
26

//初始化完成
27

for(left=1;left<=N;left++)
30

{
31

sum=sum-a[left-1];
32

if(sum >= S)
33

{
34

if(right-left+1 < min ) min=right-left+1;
35

continue;
36

}
37

for(r=right+1;r<=N;r++)
38

{
39

sum=sum+a[r];
40

if(sum>=S)
41

{ if(r-left+1 < min) min=r-left+1;
42

right=r;
43

break;
44

}
45

}
46

}
47

printf("%d\n",min);
49

}
50

return ;
52

}

posted on 2007-09-14 02:02 流牛ζ木馬閱讀(682) 評論(0) 編輯收藏引用

只有注冊用戶登錄后才能發表評論。
【推薦】100%開源！大型工業跨平臺軟件C++源碼提供，建模，組態！



網站導航: 博客園 IT新聞 BlogJava 博問 Chat2DB 管理

2007年9月

日

一

二

三

四

五

六

統計

隨筆 - 63
文章 - 0
評論 - 154
引用 - 0

公告

MY Email/MSN :mars1021@163.com QQ : 27402040 流牛ζ木馬

常用鏈接

留言簿(6)

隨筆檔案

相冊

撒旦

搜索

閱讀排行榜

評論排行榜

青青草原综合久久大伊人导航_色综合久久天天综合_日日噜噜夜夜狠狠久久丁香五月_热久久这里只有精品