看別人思路和代碼寫的。
#include <stdio.h>
int a[10];
int one[4] = {0, 7, 6, 5};
int two[4] = {0, 5, 3, 1};
int main()
{
// freopen("in", "r", stdin);
int sum, ans, needOne, needTwo;
while(1)
{
sum = 0;
for(int i = 1; i <= 6; i++)
{
scanf("%d", &a[i]);
sum += a[i];
}
if(!sum) break;
ans = a[6] + a[5] + a[4] + (a[3] + 3) / 4;
needOne = a[5] * 11 + one[a[3] % 4];
needTwo = a[4] * 5 + two[a[3] % 4];
if(needTwo <= a[2])
{
int left = a[2] - needTwo;
int tmp = (left + 8) / 9;
ans += tmp;
needOne += 4 *(9 * tmp - left);
}
else
{
needOne += 4 * (needTwo - a[2]);
}
if(needOne <= a[1])
{
ans += (a[1] - needOne + 35) / 36;
}
printf("%d\n", ans);
}
return 0;
}