• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>

            oyjpArt ACM/ICPC算法程序設計空間

            // I am new in programming, welcome to my blog
            I am oyjpart(alpc12, 四城)
            posts - 224, comments - 694, trackbacks - 0, articles - 6

            終于發現自己G題Accelarator的錯誤了 找了好久好久 就這個錯誤 讓我在整個后半段的比賽中幾乎廢掉了 太不應該了!
            吸取教訓!在場上出現自己無法找出錯誤的情況 應該要讓隊友重寫

            #include <stdio.h>
            #include <string.h>
            #include <math.h>

            const int N = 100010;
            int d[N];
            __int64 d2[N];
            int na, av, np;

            bool check(int x) {
             int i;
             for(i = 0; i < np; i++) d2[i] = d[i];
             for(i = 0; i < np; i++) d2[i] -= x;
             int cnt = 0;
             __int64 rest = na*x; 左邊寫了__int64 右邊卻忘記轉成__int64了
             for(i = 0; i<np; i++) {
              if(d2[i] > 0) {
               if(av <= 0) return false;
               __int64 need = (d2[i]-1)/av + 1;
               if(need > rest || need > x) return false;
               rest -= need;
              }
             }
             return 1;
            }

            int main() {
             int ntc, i;
             scanf("%d", &ntc);
             while(ntc--) {
              scanf("%d", &np);
              int _max = -1;
              for(i = 0; i<np; i++) {
               scanf("%d", d + i);
               if(d[i] > _max) _max = d[i];
              }
              scanf("%d %d", &na, &av);
              av--;
              int lo = 0, hi = _max;
              while(lo < hi) {
               int mid = lo + (hi-lo)/2;
               if(check(mid)) hi = mid;
               else lo = mid+1;
              }
              if(check(lo)) printf("%d\n", lo);
             }
             return 0;
            }

              
            Accelerator
            Time Limit:4000MS  Memory Limit:65536K
            Total Submit:811 Accepted:142

            Description


            Shiming (alpc02) is a boy likes to play PopKart very much. He is a good rider in this game. And one day he thought that he became a team leader of a team of N Kart riders.

            Today, after the game begins, the riders of his team are now at different places at the racetrack, for that some of the riders got some short cut.

            However, we know actually how long has each rider left to run along, and they will ride actually one meter per one time unit (maybe 10ms).

            Luckily, Shiming now gets M accelerators, the accelerator can help one rider to ride k meters per one time unit. And all the accelerators are as the same. But one rider can't use more than one accelerator at one time unit.

            Shiming is the team leader, and he wants all the team members to finish in the minimal time not just the fastest one to finish the race. He will distribute all the accelerators to the riders.

            Note: Here some rules are not as the same as the game we played. At a time unit, Shiming distributes the accelerators to riders for one rider one accelerator, and at the next time unit, all the accelerator can be reused, and Shiming can re-distributes all the accelerators to riders also for one rider one accelerator and the distribution is no relationship with the last time unit.

            So you will program to help Shiming to get the actually minimal time the team will use to finish the race.


            Input


            The input file has T (1<T<20) test cases, and the first line of the file will show the T.

            Each of test cases, will be the N (1<= N <= 100000) rider, and N numbers Ai (1<= Ai <= 10^8) show how long will the rider have to finish the race. And the M and the K (1<= K*M <=10^8) for the accelerators.


            Output
            For each of test cases print a single integer on a single line, the minimal possible number of time units required to finish the race all team.

            Sample Input


            2
            3
            2 3 9
            1 5
            3
            2 3 6
            1 5


            Sample Output


            3
            2

            Feedback

            # re: 終于發現自己G題Accelarator的錯誤了  回復  更多評論   

            2007-05-10 22:29 by
            bless,我也是錯在這個上。

            # re: 終于發現自己G題Accelarator的錯誤了  回復  更多評論   

            2007-05-11 12:25 by oyjpart
            這么巧啊 同bless
            久久久青草青青国产亚洲免观| 久久综合九色综合欧美狠狠| 久久精品国产一区二区三区| 精品欧美一区二区三区久久久 | 日本加勒比久久精品| 日韩欧美亚洲综合久久影院Ds | 久久99精品久久只有精品| 中文字幕久久精品| 丁香五月网久久综合| 久久人妻少妇嫩草AV蜜桃| 亚洲国产精品18久久久久久| 国内精品久久久久久久亚洲 | 久久99国产精品一区二区| 色99久久久久高潮综合影院| 欧美一区二区精品久久| 亚洲国产精品一区二区久久hs| 国产精品久久久久久久久软件| 成人国内精品久久久久影院VR| 99久久综合国产精品免费| 国产精品岛国久久久久| 久久婷婷五月综合色奶水99啪| 国产精品美女久久久久久2018| 日产精品久久久久久久| 国产成人久久久精品二区三区 | 国产精品久久久久jk制服| 2021国产精品久久精品| 久久久久国色AV免费看图片| 2021国产成人精品久久| 66精品综合久久久久久久| 久久久精品国产sm调教网站 | 久久精品国产只有精品66| 情人伊人久久综合亚洲| 高清免费久久午夜精品| 国内精品久久久久久99| 久久久久亚洲Av无码专| 亚洲精品乱码久久久久久中文字幕 | 一本一本久久a久久综合精品蜜桃| 亚洲伊人久久成综合人影院| 免费一级做a爰片久久毛片潮| 久久精品成人一区二区三区| 日韩欧美亚洲综合久久影院Ds|