• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 195,  comments - 30,  trackbacks - 0
            After culling his most favorite fruits from the trees in an orchard,Keen AS, a mischievous monkey, is confused of the way in which he can combine these piles of fruits into one in the most laborsaving manner. Each turn he can merely combine any two piles into a larger one. Obviously, by combining N-1 times for N piles of fruits, one pile results eventually. It always takes AS a certain quantity of units of stamina, which equals to the sum of the amounts of fruits in each of the two piles combined, to complete a combination. For instance, given three piles of fruits, containing 1, 2, and 9 fruits respectively, the combination of 1 and 2 would cost 3=1+2 units of stamina, and two piles-3 and 9-are resulted; finally, combining them would cost another 12=3+9 units of stamina, and the total units of stamina taken in the whole procedure is 15=3+12. Surely there are many a possible means to combine these three piles; however, it can be proved that 15 is the minimum amount of units of stamina in demand, and that is what your program is required to do. in this problem ,the fruits are put in a strait line. A pile of fruits 'P' can only combined with the rightest pail on the left of P or the leftest on the right of P, and the united pile will at the position of the bigger one.

            Input

            The input file consists of many test cases. The first line contains an integer N (<=100), indicating the number of piles, and the second line contains N integers, each of which represents the amount of fruits in a pile. no integer will more than 10000, the sequence of integer also means the location of the piles.

            Output

            Your program should print the minimum amount of units of stamina that are required to combine these piles of fruits into one on request.

            Sample Input

            3
            1 2 9
            

            Sample Output

            15
            

            典型的石子合并問題。
            #include<stdio.h>
            int a[101][101],sum[101];
            int stone[101];
            int main()
            {
                int n,i,j,k,flag,l,t;
                while(scanf("%d",&n)!=EOF)
                {
                    for(i=1;i<=n;i++)
                    scanf("%d",&stone[i]);
                    sum[0]=0;
                    for(i=1;i<=n;i++)
                    {
                        sum[i]=sum[i-1]+stone[i];      
                        a[i][i]=0;
                    }
                    for(l=1;l<=n-1;l++)
                    for(i=1;i<=n-l;i++)
                    {
                        flag=0;
                        j=i+l;
                        for(k=i;k<j;k++)                              
                        {
                            t=a[i][k]+a[k+1][j]+sum[j]-sum[i-1];
                            if(!flag)
                            {
                                flag=1;
                                a[i][j]=t;
                            }
                            else if(t<a[i][j])
                            a[i][j]=t;
                        }
                    }
                    printf("%d\n",a[1][n]);
                }
                return 0;
            }
            posted on 2009-06-30 21:01 luis 閱讀(487) 評論(0)  編輯 收藏 引用 所屬分類: 動態規劃
            <2009年7月>
            2829301234
            567891011
            12131415161718
            19202122232425
            2627282930311
            2345678

            常用鏈接

            留言簿(3)

            隨筆分類

            隨筆檔案

            文章分類

            文章檔案

            友情鏈接

            搜索

            •  

            最新評論

            閱讀排行榜

            評論排行榜

            亚洲午夜无码AV毛片久久| 蜜臀av性久久久久蜜臀aⅴ麻豆| 国产亚洲精久久久久久无码| 偷窥少妇久久久久久久久| 久久人人爽人人爽人人片AV高清| 久久亚洲sm情趣捆绑调教 | 99久久精品国产麻豆| 久久夜色精品国产噜噜麻豆| 久久综合香蕉国产蜜臀AV| 精品精品国产自在久久高清| 久久久久国产一区二区三区| 久久精品极品盛宴观看| 嫩草伊人久久精品少妇AV| 91精品国产91久久| 久久经典免费视频| 久久精品国产精品青草app| 欧美日韩精品久久久免费观看| 天堂久久天堂AV色综合| 精品久久国产一区二区三区香蕉 | 国产午夜久久影院| 狠狠精品久久久无码中文字幕 | 久久久久一区二区三区| 亚洲午夜精品久久久久久浪潮| 久久精品人人做人人爽电影蜜月| 国产精品美女久久久网AV| 亚洲乱码精品久久久久..| 久久国产精品偷99| 久久精品国产亚洲精品2020| 午夜精品久久影院蜜桃| 日本久久久久久中文字幕| 人妻少妇久久中文字幕| 亚洲国产成人乱码精品女人久久久不卡 | 91精品国产综合久久久久久| 亚洲精品久久久www| 中文字幕亚洲综合久久2| 国产精品久久成人影院| 亚洲乱码精品久久久久..| 热久久视久久精品18| 欧美精品丝袜久久久中文字幕| 香蕉久久一区二区不卡无毒影院 | 久久se精品一区精品二区国产|