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            Uriel's Corner

            Research Associate @ Harvard University / Research Interests: Computer Vision, Biomedical Image Analysis, Machine Learning
            posts - 0, comments - 50, trackbacks - 0, articles - 594

            POJ 3344 Chessboard Dance---模擬

            Posted on 2009-11-10 19:24 Uriel 閱讀(390) 評(píng)論(0)  編輯 收藏 引用 所屬分類: POJ模擬

            PKU第602題。。大牛前輩jjllqq的PKU切題數(shù)目。。但是差距無(wú)法計(jì)算。。一個(gè)大牛一個(gè)大水。。。

            期中考試前某晚上想著AC602再?gòu)?fù)習(xí)。。于是乎。。這題搞了幾個(gè)小時(shí)。。只想到純模擬的方法。。代碼增加到7404B。。(去注釋之前8575B)終于過了。。

            又丑又長(zhǎng)的代碼(純屬紀(jì)念)
            /*Problem: 3344  User: Uriel 
               Memory: 360K  Time: 0MS 
               Language: G++  Result: Accepted
            */
             

            #include
            <stdio.h>
            #include
            <stdlib.h>
            #include
            <string.h>

            struct point 
            {
                
            int x,y;
                
            int dir;
            }
            ;

            char b[9][9];
            point pos;
            char str[10],cmd[10];
            int step;
            int dis[9][9];

            int main()
            {
                
            int i,j,k;
                
            while(1)
                
            {
                    
            for(i=1;i<=8;++i)
                    
            {
                        
            for(j=1;j<=8;++j)
                        
            {
                            scanf(
            "%c",&b[i][j]);
                            
            if(i==1 && j==2 && b[1][1]=='-' && b[1][2]=='-')
                            
            {
            //                    printf("*");
             
            //                   system("PAUSE");
                                return 0;
                            }

                            
            if(b[i][j]=='v')
                            
            {
                                pos.dir
            =0;
                                pos.x
            =j;
                                pos.y
            =i;
                            }

                            
            else if(b[i][j]=='<')
                            
            {
                                pos.dir
            =1;
                                pos.x
            =j;
                                pos.y
            =i;
                            }

                            
            else if(b[i][j]=='^')
                            
            {
                                pos.dir
            =2;
                                pos.x
            =j;
                                pos.y
            =i;
                            }

                            
            else if(b[i][j]=='>')
                            
            {
                                pos.dir
            =3;
                                pos.x
            =j;
                                pos.y
            =i;
                            }

                        }

                        getchar();
                    }

                    
            while(1)
                    
            {
                        scanf(
            "%s",str);
                        
            if(strcmp(str,"#")==0)
                        
            {
            //                printf("*");
                            break;
                        }

                        
            if(strcmp(str,"move")==0)
                        
            {
                            scanf(
            "%d",&step);
                            
            if(pos.dir==3)
                            
            {
                                b[pos.y][pos.x]
            ='.';
                                k
            =0;//從pos點(diǎn)到右邊界有多少空格 
                                for(i=pos.x+1;i<=8;++i)
                                
            {
                                    
            if(b[pos.y][i]=='.')
                                    
            {
                                        k
            ++;
                                        
            if(k>=step)break;
                                    }

                                    
            else
                                    
            {
                                        dis[pos.y][i]
            =k;
                                    }

                                }

                                
            for(j=i-1;j>pos.x;--j)
                                
            {
                                    
            if(b[pos.y][j]=='.')continue;
                                    
            if(j+(step-dis[pos.y][j])>8)
                                    
            {
                                        b[pos.y][j]
            ='.';
                                        
            continue;
                                    }

                                    b[pos.y][j
            +(step-dis[pos.y][j])]=b[pos.y][j];
                                    b[pos.y][j]
            ='.';
                                }

                                pos.x
            +=step;
                                
            if(pos.x>8)pos.x=8;
                            }

                            
            else if(pos.dir==1)
                            
            {
                                b[pos.y][pos.x]
            ='.';
                                k
            =0;//從pos點(diǎn)到左邊界有多少空格 
                                for(i=pos.x-1;i>=1;--i)
                                
            {
                                    
            if(b[pos.y][i]=='.')
                                    
            {
                                        k
            ++;
                                        
            if(k>=step)break;
                                    }

                                    
            else
                                    
            {
                                        dis[pos.y][i]
            =k;
                                    }

                                }

                                
            for(j=i+1;j<pos.x;++j)
                                
            {
                                    
            if(b[pos.y][j]=='.')continue;
                                    
            if(j-(step-dis[pos.y][j])<=0)
                                    
            {
                                        b[pos.y][j]
            ='.';
                                        
            continue;
                                    }

                                    b[pos.y][j
            -(step-dis[pos.y][j])]=b[pos.y][j];
                                    b[pos.y][j]
            ='.';
                                }

                                pos.x
            -=step;
                                
            if(pos.x<=0)pos.x=1;
                            }

                            
            else if(pos.dir==2)
                            
            {
                                b[pos.y][pos.x]
            ='.';
                                k
            =0;//從pos點(diǎn)到上邊界有多少空格 
                                for(i=pos.y-1;i>=1;--i)
                                
            {
                                    
            if(b[i][pos.x]=='.')
                                    
            {
                                        k
            ++;
                                        
            if(k>=step)break;
                                    }

                                    
            else
                                    
            {
                                        dis[i][pos.x]
            =k;
                                    }

                                }

                                
            for(j=i+1;j<pos.y;++j)
                                
            {
                                    
            if(b[j][pos.x]=='.')continue;
                                    
            if(j-(step-dis[j][pos.x])<=0)
                                    
            {
                                        b[j][pos.x]
            ='.';
                                        
            continue;
                                    }

                                    b[j
            -(step-dis[j][pos.x])][pos.x]=b[j][pos.x];
                                    b[j][pos.x]
            ='.';
                                }

                                pos.y
            -=step;
                                
            if(pos.y<=0)pos.y=1;
                            }

                            
            else if(pos.dir==0)
                            
            {
                                b[pos.y][pos.x]
            ='.';
                                k
            =0;//從pos點(diǎn)到下邊界有多少空格 
                                for(i=pos.y+1;i<=8;++i)
                                
            {
                                    
            if(b[i][pos.x]=='.')
                                    
            {
                                        k
            ++;
                                        
            if(k>=step)break;
                                    }

                                    
            else
                                    
            {
                                        dis[i][pos.x]
            =k;
                                    }

                                }

                                
            for(j=i-1;j>pos.y;--j)
                                
            {
                                    
            if(b[j][pos.x]=='.')continue;
                                    
            if(j+(step-dis[j][pos.x])>8)
                                    
            {
                                        b[j][pos.x]
            ='.';
                                        
            continue;
                                    }

                                    b[j
            +(step-dis[j][pos.x])][pos.x]=b[j][pos.x];
                                    b[j][pos.x]
            ='.';
                                }

                                pos.y
            +=step;
                                
            if(pos.y>8)pos.y=8;
                            }
             
                        }

                        
            if(strcmp(str,"turn")==0)   
                        
            {
                            scanf(
            "%s",cmd);
                            
            if(strcmp(cmd,"left")==0)
                            
            {                    
                                pos.dir
            =(pos.dir+3)%4;
                            }

                            
            else if(strcmp(cmd,"right")==0)
                            
            {                    
                                pos.dir
            =(pos.dir+1)%4;
                            }

                            
            else if(strcmp(cmd,"back")==0)
                            
            {                    
                                pos.dir
            =(pos.dir+2)%4;
                            }

                        }

                    }

                    
            for(i=1;i<=8;++i)
                    
            {
                        
            for(j=1;j<=8;++j)
                        
            {
                            
            if(pos.x==&& pos.y==i)
                            
            {
                                
            if(pos.dir==0)
                                
            {
                                    printf(
            "v");
                                }

                                
            else if(pos.dir==1)
                                
            {
                                    printf(
            "<");
                                }

                                
            else if(pos.dir==2)
                                
            {
                                    printf(
            "^");
                                }

                                
            else if(pos.dir==3)
                                
            {
                                    printf(
            ">");
                                }

                            }

                            
            else
                            
            {
                                printf(
            "%c",b[i][j]);
                            }

                        }

                        printf(
            "\n");
                    }
               
                    printf(
            "\n"); 
                    getchar();               
                }

            }

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