題意為求點的最小外接球。
本想隨機模擬退火，可是怎么也掌握不好火候。
后來改為每次定向變步長，取的點向離它最遠的那個點移動。
初始隨機了10個點。
  POJ 2069
#include<iostream>
#include<time.h>
#include<cmath>
#define sqr(x) (x)*(x)
#define FOR(i,a,b) for(int i=a;i<b;i++)
#define FF(i,a) for(int i=0;i<a;i++)
using namespace std;
const double eps=1e-6;
const double INF=1e20;
const double pi=acos(-1.0);
struct Houxuan
{
double x,y,z,dist;
}pp[10];
struct PT
{
double x,y,z;
}hole[30];
double dis(double x1,double y1,double z1,double x2,double y2,double z2)
{
return sqrt(sqr(x1-x2)+sqr(y1-y2)+sqr(z1-z2));
}
int n;
int main()
{
int P=10;
while(scanf("%d",&n)&&n)
{
double delta=100.0;
FF(i,n)
scanf("%lf%lf%lf",&hole[i].x,&hole[i].y,&hole[i].z);
FF(i,P)
{
pp[i].x=double(rand()%10000+1)/10000.0*100;
pp[i].y=double(rand()%10000+1)/10000.0*100;
pp[i].z=double(rand()%10000+1)/10000.0*100;
pp[i].dist=0;
FF(j,n)
pp[i].dist=max(pp[i].dist,dis(pp[i].x,pp[i].y,pp[i].z,hole[j].x,hole[j].y,hole[j].z));
}
while(delta>eps)
{
FF(i,P)
{
int idx=0;
double tmp=0;
FF(j,n)
{
double d=dis(hole[j].x,hole[j].y,hole[j].z,pp[i].x,pp[i].y,pp[i].z);
if(d>tmp)
{
idx=j;
tmp=d;
}
}
pp[i].dist=min(pp[i].dist,tmp);
pp[i].x=pp[i].x+(hole[idx].x-pp[i].x)/tmp*delta;
pp[i].y=pp[i].y+(hole[idx].y-pp[i].y)/tmp*delta;
pp[i].z=pp[i].z+(hole[idx].z-pp[i].z)/tmp*delta;
}
delta*=0.98;
}
int idx=0;
FOR(i,1,P)
{
if(pp[i].dist<pp[idx].dist)
idx=i;
}
printf("%.5lf\n",pp[idx].dist);
}
return 0;
}
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