再次經過優化的 c++ 源碼

#include <iostream>
#include <stdlib.h>
#include <vector>
using namespace std;

// 模擬ASM的 PUSH, POP 操作
template<class T>
class Stack
{
public:
?void push(T data)
?{
? vstack.push_back(data);
?}

?void pop(T& data)
?{
? if (vstack.empty())
? {
?? data = 0;
? }
? else
? {
?? data = vstack.back();
?? vstack.pop_back();
? }
?}

private:
?vector<T> vstack;
};

typedef unsigned long DWORD;

Stack<DWORD> thisStack;

__int64 n402182 = 0xFEDCBA98;

std::vector<DWORD> g_stack;

void XChange(DWORD& a, DWORD& b)
{
?DWORD c = 0;
?c = a;
?a = b;
?b = c;
}

int SHR(DWORD& a)
{
?int nBit = a & 0x01;
?a >>= 0x01;
?return nBit;
}

void XOR_HIGH_LOW(DWORD& a)
{
?char value[2] = {0};
?memcpy(value, &a, sizeof(short));
?value[1] |= value[0];
?memcpy(&a, value, sizeof(short));
?
}

DWORD fun(DWORD nECX)
{
??? DWORD nRtn = nECX;

??? if( nECX <= 0x80 )?????? // cmp ecx, 80
??????? return nRtn;???????? // jle short 004011F0

??? thisStack.push(nECX);??? //? push ecx
??? DWORD nESI? = nECX;????? //? mov esi, ecx
??? nECX &= 0xFF;??????????? //? and ecx, 0FF
??? DWORD nEDI = 0x549417E7; // nEAX 值?? mov edi, eax? //////////////////////? EAX 值
???
??? if( !(nECX <= 0x08) )??????????? // cmp ecx, 8; jle short 004011B0
?{
??nEDI = 0x02F23D32;???????? // nEBX 值? mov edi, ebx /////////////////////?? EBX 值
??nECX >>= 0x04;???????????? // shr ecx, 4
?}

?int nBit = 0;
?do
?{
??_asm rol nEDI, 8?????????? // rol edi, 8
??nBit = SHR(nECX);????? // SHR ecx, 1???
?}
??? while( !nBit );???????? //jnz short 004011B0
???
??? nESI >>= 0x08;?
??? nEDI &= nESI;
??? nEDI &= 0xFF;
??? thisStack.pop(nECX);

??? nESI = 0x80;??? // mov esi, 80
?
?do
?{
??int nResult = (nESI & nEDI);

??while( !(nResult == 0x00) )?????????? // test esi, edi; je short 004011EC
??{
???nEDI ^= nESI;
???thisStack.push(nEDI);??????? // push edi
???
???nECX &= 0xFF00;????????????? // and ecx, 0FF00
???
???XChange(nESI, nECX);???????? // xchg esi, ecx
???XOR_HIGH_LOW(nECX);????????? // xor ch, cl
???nESI ^= nECX;??????????????? // xor esi, ecx
???XChange(nECX, nESI);???????? // xchg ecx, esi
???
???n402182++;?? // push ecx; inc dword ptr [402182]???????? // n402182 地址
???nECX = fun(nECX);?? // call 00401190
???
???thisStack.pop(nEDI); // pop edi

???nESI = 0x80;??? // mov esi, 80
???nResult = (nESI & nEDI);
??}

?}while( SHR(nESI) != 1);

?return nECX;
}

void main()
{
?printf("0x%x\n", fun(0x0FF01));
}

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