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            心如止水
            Je n'ai pas le temps
            posts - 400,comments - 130,trackbacks - 0
            從string中尋找"P="、"U="、"I=",然后記錄P、U、I的值,使用istringstream比較方便。
            以下是我的代碼:
            #include<iostream>
            #include
            <sstream>
            #include
            <string>
            #include
            <cstdio>
            using namespace std;

            int main()
            {
                
            /*
                freopen("data.in","r",stdin);
                freopen("data.out","w",stdout);
                //
            */

                
            int T;
                cin
            >>T;getchar();
                
            for(int case_num=1;case_num<=T;case_num++)
                {
                    
            string line;
                    getline(cin,line);
                    
            double P(-1.0),U(-1.0),I(-1.0);
                    istringstream sin(line);
                    
            char ch;
                    
            while(sin>>ch)
                    {
                        
            if(ch=='P')
                        {
                            
            char t;
                            sin
            >>t;
                            
            if(t!='=')
                                
            continue;
                            sin
            >>P;
                            sin
            >>t;
                            
            if(t=='m')
                                P
            /=1000;
                            
            else if(t=='k')
                                P
            *=1000;
                            
            else if(t=='M')
                                P
            *=1000000;
                        }
                        
            else if(ch=='U')
                        {
                            
            char t;
                            sin
            >>t;
                            
            if(t!='=')
                                
            continue;
                            sin
            >>U;
                            sin
            >>t;
                            
            if(t=='m')
                                U
            /=1000;
                            
            else if(t=='k')
                                U
            *=1000;
                            
            else if(t=='M')
                                U
            *=1000000;
                        }
                        
            else if(ch=='I')
                        {
                            
            char t;
                            sin
            >>t;
                            
            if(t!='=')
                                
            continue;
                            sin
            >>I;
                            sin
            >>t;
                            
            if(t=='m')
                                I
            /=1000;
                            
            else if(t=='k')
                                I
            *=1000;
                            
            else if(t=='M')
                                I
            *=1000000;
                        }
                    }

                    cout
            <<"Problem #"<<case_num<<endl;
                    
            if(P==-1.0)
                        printf(
            "P=%.2fW\n",U*I);
                    
            else if(U==-1.0)
                        printf(
            "U=%.2fV\n",P/I);
                    
            else
                        printf(
            "I=%.2fA\n",P/U);
                    printf(
            "\n");
                }

                
            return 0;
            }
            posted on 2011-04-07 12:53 lee1r 閱讀(706) 評論(0)  編輯 收藏 引用 所屬分類: 題目分類:字符串處理
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