很經(jīng)典的題目吧，我把代碼貼上來(lái)了。
考察隊(duì)列和棧的基本操作，記得《算法藝術(shù)》上有講解。
以下是我的代碼：
#include<iostream>
#include<string>
#include<queue>
#include<stack>
#include<cstdio>
using namespace std;
int main()
{
/*
freopen("data.in","r",stdin);
freopen("data.out","w",stdout);
//*/
int n;
while(cin>>n)
{
string order1,order2;
cin>>order1>>order2;
queue<char> q;
for(int i=0;i<order1.size();i++)
q.push(order1[i]);
stack<char> s;
int pos(0),ans[100]={0},ans_len(0);
bool success=true;
while(!q.empty())
{
if(!s.empty()&&s.top()==order2[pos])
{
s.pop();
pos++;
ans[++ans_len]=0;
}
else
{
s.push(q.front());
q.pop();
ans[++ans_len]=1;
}
}
while(!s.empty())
{
if(s.top()==order2[pos])
{
s.pop();
pos++;
ans[++ans_len]=0;
}
else
{
success=false;
break;
}
}
if(success)
{
cout<<"Yes."<<endl;
for(int i=1;i<=ans_len;i++)
if(ans[i]==1)
cout<<"in"<<endl;
else cout<<"out"<<endl;
}
else cout<<"No."<<endl;
cout<<"FINISH"<<endl;
}
return 0;
}