• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 195,  comments - 30,  trackbacks - 0

             

            #include<iostream>
            #include
            <cstdlib>
            #include 
            <memory> 
            using namespace std;
              
            int a[201];
              
            int main()
              
            {
              
            //freopen("s.txt","r",stdin);
              
            //freopen("key.txt","w",stdout);
              int n,m,i,j,k,temp;
              cin
            >>n;
              
            while(n--)
              
            {
                 temp
            =0;       
                 memset(a,
            0,sizeof(a));              
                 cin
            >>m;
                 
            while(m--)
                 
            {
                        cin
            >>i>>j;
                        
            if(i%2==0)
                          i
            =i/2;
                          
            else i=i/2+1;
                        
            if(j%2==0)
                           j
            =j/2;
                           
            else 
                             j
            =j/2+1;
                        
            if(i>j)
                        
            {temp=i;
                        i
            =j;
                        j
            =temp;
                        temp
            =0;
                        }
                 
                        
            for(k=i;k<=j;k++)
                        a[k]
            ++;  
                 }

                 
            for(k=1;k<=200;k++)
                 
            if(a[k]>temp)temp=a[k];
                 cout
            <<temp*10<<endl;                 
              }


              
            //system("PAUSE");
              return   0;
              }

            Moving Tables


            Status In/Out TIME Limit MEMORY Limit Submit Times Solved Users JUDGE TYPE
            stdin/stdout 3s 8192K 899 213 Standard

            The famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in the following figure.

            The floor has 200 rooms each on the north side and south side along the corridor. Recently the Company made a plan to reform its system. The reform includes moving a lot of tables between rooms. Because the corridor is narrow and all the tables are big, only one table can pass through the corridor. Some plan is needed to make the moving efficient. The manager figured out the following plan: Moving a table from a room to another room can be done within 10 minutes. When moving a table from room i to room j, the part of the corridor between the front of room i and the front of room j is used. So, during each 10 minutes, several moving between two rooms not sharing the same part of the corridor will be done simultaneously. To make it clear the manager illustrated the possible cases and impossible cases of simultaneous moving.


            For each room, at most one table will be either moved in or moved out. Now, the manager seeks out a method to minimize the time to move all the tables. Your job is to write a program to solve the manager’s problem.

            Input

            The input consists of T test cases. The number of test cases ) (T is given in the first line of the input file. Each test case begins with a line containing an integer N , 1<=N<=200 , that represents the number of tables to move. Each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t (each room number appears at most once in the N lines). From the N+3-rd line, the remaining test cases are listed in the same manner as above.

             

            Output

            The output should contain the minimum time in minutes to complete the moving, one per line.

            Sample Input

            3
            4
            10 20
            30 40
            50 60
            70 80
            2
            1 3
            2 200
            3
            10 100
            20 80
            30 50
            

            Sample Output

            10
            20
            30
            
            題真的很簡單,有一個陷阱就是他給的s和t的大小不一定都是s<=t的,

            一定要仔細慎重啊

            低級錯誤
            posted on 2009-05-11 11:36 luis 閱讀(337) 評論(0)  編輯 收藏 引用
            <2009年5月>
            262728293012
            3456789
            10111213141516
            17181920212223
            24252627282930
            31123456

            常用鏈接

            留言簿(3)

            隨筆分類

            隨筆檔案

            文章分類

            文章檔案

            友情鏈接

            搜索

            •  

            最新評論

            閱讀排行榜

            評論排行榜

            久久精品99久久香蕉国产色戒| 日韩精品久久久久久久电影蜜臀| 亚洲一本综合久久| 久久综合成人网| 国产一区二区精品久久| 久久精品不卡| 国产精品久久久久9999| 久久这里有精品视频| 久久精品人人做人人妻人人玩| 久久精品国产精品亚洲人人| 欧洲人妻丰满av无码久久不卡| 成人a毛片久久免费播放| 亚洲av成人无码久久精品| 国产福利电影一区二区三区久久久久成人精品综合 | 久久本道久久综合伊人| 中文字幕久久久久人妻| 久久国产视频99电影| 五月丁香综合激情六月久久| 久久久久久噜噜精品免费直播| 久久亚洲精品成人AV| 欧美亚洲国产精品久久| 久久精品成人免费观看97| 久久午夜电影网| 狠狠干狠狠久久| A狠狠久久蜜臀婷色中文网| 欧美精品国产综合久久| 久久精品国产清自在天天线| 久久综合综合久久97色| 国产成人久久精品一区二区三区 | 99久久久国产精品免费无卡顿| 久久人与动人物a级毛片| 99久久精品九九亚洲精品| 久久精品aⅴ无码中文字字幕重口| 国内精品久久久久国产盗摄| 99久久精品免费国产大片| 狠狠色丁香婷婷久久综合不卡| 国产aⅴ激情无码久久| 久久夜色精品国产www| 久久露脸国产精品| 久久久久无码精品| 狠狠久久综合|