• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>

            poj2418

            Hardwood Species

            Time Limit: 10000MS Memory Limit: 65536K
            Total Submissions: 13263 Accepted: 5434

            Description

            Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter.
            America's temperate climates produce forests with hundreds of hardwood species -- trees that share certain biological characteristics. Although oak, maple and cherry all are types of hardwood trees, for example, they are different species. Together, all the hardwood species represent 40 percent of the trees in the United States.

            On the other hand, softwoods, or conifers, from the Latin word meaning "cone-bearing," have needles. Widely available US softwoods include cedar, fir, hemlock, pine, redwood, spruce and cypress. In a home, the softwoods are used primarily as structural lumber such as 2x4s and 2x6s, with some limited decorative applications.

            Using satellite imaging technology, the Department of Natural Resources has compiled an inventory of every tree standing on a particular day. You are to compute the total fraction of the tree population represented by each species.

            Input

            Input to your program consists of a list of the species of every tree observed by the satellite; one tree per line. No species name exceeds 30 characters. There are no more than 10,000 species and no more than 1,000,000 trees.

            Output

            Print the name of each species represented in the population, in alphabetical order, followed by the percentage of the population it represents, to 4 decimal places.

            Sample Input

            Red Alder
            Ash
            Aspen
            Basswood
            Ash
            Beech
            Yellow Birch
            Ash
            Cherry
            Cottonwood
            Ash
            Cypress
            Red Elm
            Gum
            Hackberry
            White Oak
            Hickory
            Pecan
            Hard Maple
            White Oak
            Soft Maple
            Red Oak
            Red Oak
            White Oak
            Poplan
            Sassafras
            Sycamore
            Black Walnut
            Willow
            

            Sample Output

            Ash 13.7931
            Aspen 3.4483
            Basswood 3.4483
            Beech 3.4483
            Black Walnut 3.4483
            Cherry 3.4483
            Cottonwood 3.4483
            Cypress 3.4483
            Gum 3.4483
            Hackberry 3.4483
            Hard Maple 3.4483
            Hickory 3.4483
            Pecan 3.4483
            Poplan 3.4483
            Red Alder 3.4483
            Red Elm 3.4483
            Red Oak 6.8966
            Sassafras 3.4483
            Soft Maple 3.4483
            Sycamore 3.4483
            White Oak 10.3448
            Willow 3.4483
            Yellow Birch 3.4483
            

            Hint

            This problem has huge input, use scanf instead of cin to avoid time limit exceeded.

            Source

            Waterloo Local 2002.01.26

            所有字符都有
            水的trie樹+dfs
            #include <cstdio>
            #include 
            <cstdlib>
            #include 
            <cstring>
            #include 
            <cmath>
            #include 
            <ctime>
            #include 
            <cassert>
            #include 
            <iostream>
            #include 
            <sstream>
            #include 
            <fstream>
            #include 
            <map>
            #include 
            <set>
            #include 
            <vector>
            #include 
            <queue>
            #include 
            <algorithm>
            #include 
            <iomanip>
            #define maxn 40000
            using namespace std;
            struct node
            {
                
            int next[256];
                
            int count;
                
            void init()
                
            {
                    memset(next,
            -1,sizeof(next));
                    count
            =0;
                }

            }
            s[maxn];
            int sind;
            int num,ans,n;
            char str[50];
            void cas_init()
            {
                s[
            0].init();
                sind
            =1;
            }

            int ins(char str[])
            {
                
            int i,j,ind;
                ind
            =0;
                
            for(int i=0;i<strlen(str);i++)
                
            {
                    j
            =str[i];
                    
            if(s[ind].next[j]==-1)
                    
            {
                        s[sind].init();
                        s[ind].next[j]
            =sind++;
                    }

                    ind
            =s[ind].next[j];
                }

                
            if(s[ind].count!=0)
                
            {
                    s[ind].count
            ++;
                    
            return 0;
                }

                
            else
                
            {
                    s[ind].count
            ++;
                    
            return 1;
                }

            }

            void dfs(int id,int depth)
            {
                
            if(s[id].count>0)
                
            {
                    str[depth]
            ='\0';
                    printf(
            "%s %.4lf\n",str,(s[id].count*100.0/double(num)));
                }

                
            for(int i=0;i<256;i++)
                
            if(s[id].next[i]!=-1)
                
            {
                    str[depth]
            =i;
                    dfs(s[id].next[i],depth
            +1);
                }

            }

            int main()
            {
                
            int flag;
                
            char str[40];
                n
            =0;num=0;
                
            //printf("%d",strcmp("!","@"));
                
            //freopen("in1.txt","r+",stdin);
                cas_init();
                
            while(gets(str))
                
            {
                    num
            ++;
                    flag
            =ins(str);
                    
            if(flag==1) n++;
                }

                dfs(
            0,0);
                
            //fclose(stdin);
                return 0;
            }


            posted on 2012-07-24 13:53 jh818012 閱讀(176) 評論(0)  編輯 收藏 引用


            只有注冊用戶登錄后才能發(fā)表評論。
            網(wǎng)站導(dǎo)航: 博客園   IT新聞   BlogJava   博問   Chat2DB   管理


            <2025年7月>
            293012345
            6789101112
            13141516171819
            20212223242526
            272829303112
            3456789

            導(dǎo)航

            統(tǒng)計

            常用鏈接

            留言簿

            文章檔案(85)

            搜索

            最新評論

            • 1.?re: poj1426
            • 我嚓,,輝哥,,居然搜到你的題解了
            • --season
            • 2.?re: poj3083
            • @王私江
              (8+i)&3 相當于是 取余3的意思 因為 3 的 二進制是 000011 和(8+i)
            • --游客
            • 3.?re: poj3414[未登錄]
            • @王私江
              0ms
            • --jh818012
            • 4.?re: poj3414
            • 200+行,跑了多少ms呢?我的130+行哦,你菜啦,哈哈。
            • --王私江
            • 5.?re: poj1426
            • 評論內(nèi)容較長,點擊標題查看
            • --王私江
            少妇无套内谢久久久久| 亚洲狠狠综合久久| 国产精品成人久久久久三级午夜电影| 亚洲国产成人久久综合区| 亚洲国产成人久久综合碰碰动漫3d| 97久久超碰成人精品网站| 久久综合久久综合久久| 日本精品久久久久久久久免费| 久久99国产精品99久久| 激情久久久久久久久久| 亚洲国产精品无码久久| 久久精品无码一区二区app| 久久国产高清字幕中文| 国产成年无码久久久免费| 久久久久九国产精品| 久久亚洲AV成人无码| 91久久精品国产免费直播| 久久综合给合久久国产免费| 日韩人妻无码一区二区三区久久99| 久久久无码精品亚洲日韩按摩| 久久久久久久亚洲Av无码| 人妻精品久久无码区| 久久综合狠狠综合久久综合88 | 人妻久久久一区二区三区| 欧美精品丝袜久久久中文字幕| 久久精品无码一区二区日韩AV| 九九久久99综合一区二区| 久久91综合国产91久久精品| 国产成人精品久久| 青青青青久久精品国产h久久精品五福影院1421 | 2020久久精品亚洲热综合一本| 久久久久久曰本AV免费免费| 一本久久a久久精品亚洲| 97久久香蕉国产线看观看| 精品久久久久久无码中文野结衣| 色综合久久久久综合99| 久久99精品久久久大学生| 99精品伊人久久久大香线蕉| 午夜精品久久久久久| 婷婷久久综合九色综合98| 人妻中文久久久久|