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構(gòu)造，復(fù)制構(gòu)造，賦值函數(shù)例子

* Doc Name: Basic Concepts: constructor, copy constructor,

* assignment operation

* Prob Id: -

* Serial Id: A.2.2

* Author: -

* Env: Microsoft Visual Studio 2008 Win32 Console

* Date: 10/10/27

#include "stdafx.h"

#include <iostream>

using namespace std;

class A

{

public:

A(){cout<<"ctor"<<endl;}

A(int i){cout<<"ctor int"<<endl;}

A(const A& src){cout<<"copy ctor"<<endl;}

A& operator=(const A& rhs){cout<<"assgin op"<<endl; return (*this);}

};

void println(const int n)

{

cout<<"------- case "<<n<<"-------"<<endl;

}

A& getInstRef()

{

A* p = new A();

return *p;

}

A getInst()

{

A* p = new A();

return *p;

}

int _tmain(int argc, _TCHAR* argv[])

{

println(1);

A instA; //ctor in stack

println(2);

A* pint; //nothing done

println(3);

pint = new A(); //ctor heap

println(4);

A instAA(instA); //copy ctor

println(5);

A instAAA = instA; //copy ctor

println(6);

instAA = instAAA; //assign op

println(7);

A instAAAA = getInstRef(); //temp instance - return refrence to construct

println(8);

instAAAA = getInstRef(); //temp instance - return refrence to copy construct

println(9);

A instA5 = getInst(); //temp instance - return instance to construct

println(10);

instA5 = getInst(); //temp instance - return instance to copy construct

println(11);

A instA6 = 3;

println(12);

A instA7;

instA7 = 4;

return 0;

}

posted on 2010-10-27 20:37 elprup 閱讀(179) 評論(0) 編輯收藏引用

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