//一、當(dāng)n mod 6 != 2 且 n mod 6 != 3時(shí)，有一個(gè)解為：
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//2,4,6,8,...,n,1,3,5,7,...,n-1 (n為偶數(shù))
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//2,4,6,8,...,n-1,1,3,5,7,...,n (n為奇數(shù))
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//(上面序列第i個(gè)數(shù)為ai，表示在第i行ai列放一個(gè)皇后；... 省略的序列中，相鄰兩數(shù)以2遞增。下同)
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//二、當(dāng)n mod 6 == 2 或 n mod 6 == 3時(shí)，
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//(當(dāng)n為偶數(shù),k=n/2；當(dāng)n為奇數(shù),k=(n-1)/2)
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//k,k+2,k+4,...,n,2,4,...,k-2,k+3,k+5,...,n-1,1,3,5,...,k+1 (k為偶數(shù),n為偶數(shù))
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//k,k+2,k+4,...,n-1,2,4,...,k-2,k+3,k+5,...,n-2,1,3,5,...,k+1,n (k為偶數(shù),n為奇數(shù))
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//k,k+2,k+4,...,n-1,1,3,5,...,k-2,k+3,...,n,2,4,...,k+1 (k為奇數(shù),n為偶數(shù))
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//k,k+2,k+4,...,n-2,1,3,5,...,k-2,k+3,...,n-1,2,4,...,k+1,n (k為奇數(shù),n為奇數(shù))