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            The Fourth Dimension Space

            枯葉北風寒,忽然年以殘,念往昔,語默心酸。二十光陰無一物,韶光賤,寐難安; 不畏形影單,道途阻且慢,哪曲折,如渡飛湍。斬浪劈波酬壯志,同把酒,共言歡! -如夢令

            POJ 3126-Prime Path 廣度優先搜索BFS

            不知道數論里面是不是有相關的公式,總之這道題我做的有點暴力,呵呵,一個BFS搞定;
            要說具體的算法的話,就是【】【】【】【】這 四個數位按從左到右的順序每次改變一個位置上的數字,如果這個數字是質數,就把它放入隊列,并記錄下到達這個數字所要經歷的步數即可,然后循環搜索,搜到跳出。。。
            有點遺憾的是,這道題我寫的有點長,如果你有更好的想法,不妨告訴我哦 謝謝啦O(∩_∩)O~

            #include <iostream>
            #include 
            <algorithm>
            #include
            <cstdio>
            using namespace std;

            bool prim[10000];

            struct node
            {
                
            int n;
                
            int step;

            }
            line[100001];

            int visited[10000];

            int main()
            {
                
            int n,m;
                
            int i,j;
                
            for(i=2;i<=10000;i++)
                
            {
                    
            if(prim[i]==true)
                        
            continue;
                    
            for(j=2;j<=10000;j++)
                    
            {
                        
            if(i*j>10000)
                            
            break;
                        prim[i
            *j]=true;
                    }

                }




                
            /////////////////////////////////////////////////////////////////////////////////////////
                int testcase;
                
            int front;
                
            int rear;
                scanf(
            "%d",&testcase);
                
            for(j=1;j<=testcase;j++)
                
            {
                    memset(visited,
            false,sizeof(visited));
                    
            for(i=1;i<=10000;i++)
                    
            {
                        line[i].n
            =0;
                        line[i].step
            =0;
                    }


                    front
            =1;
                    rear
            =1;
                    scanf(
            "%d%d",&n,&m);
                    line[
            1].n=n;
                    line[
            1].step=0;


                    
            while(front<=rear)
                    
            {
                        
            if(line[front].n==m)
                            
            break;

                        
            if(visited[line[front].n]==0)
                        
            {
                            visited[line[front].n]
            =1;
                            
            int k;
                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n-k*1000>=1000)
                                
            {
                                    
            if (prim[line[front].n-k*1000]==0&&visited[line[front].n-k*1000]==false)
                                    
                                    
            {

                                    

                                    rear
            ++;
                                    line[rear].n
            =line[front].n-k*1000;
                                    line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n+k*1000<10000)

                                
            {
                                    
            if(prim[line[front].n+k*1000]==0&&visited[line[front].n+k*1000]==false)
                                    
            {

                                    

                                    rear
            ++;
                                    line[rear].n
            =line[front].n+k*1000;
                                    line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;


                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%1000-k*100>=0)
                                
            {
                                    
            if(prim[line[front].n-k*100]==0&&visited[line[front].n-k*100]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n-k*100;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%1000+k*100<1000)
                                
            {
                                    
            if(prim[line[front].n+k*100]==0&&visited[line[front].n+k*100]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n+k*100;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%100-k*10>=0)
                                
            {
                                    
            if(prim[line[front].n-k*10]==0&&visited[line[front].n-k*10]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n-k*10;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%100+k*10<100)
                                
            {
                                    
            if(prim[line[front].n+k*10]==0&&visited[line[front].n+k*10]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n+k*10;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%10-k*1>=0)
                                
            {
                                    
            if(prim[line[front].n-k*1]==0&&visited[line[front].n-k*1]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n-k*1;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                            
            for(k=1;;k++)
                            
            {
                                
            if(line[front].n%10+k*1<10)
                                
            {
                                    
            if(prim[line[front].n+k*1]==0&&visited[line[front].n+k*1]==false)
                                    
            {
                                        rear
            ++;
                                        line[rear].n
            =line[front].n+k*1;
                                        line[rear].step
            =line[front].step+1;
                                    }

                                }

                                
            else
                                    
            break;
                            }

                        }

                    front
            ++;
                    }

                    
            if(front>rear)
                        printf(
            "Impossible\n");
                    
            else
                        printf(
            "%d\n",line[front].step);

                }

                system(
            "pause");
                
            return 0;
            }





            posted on 2009-02-27 22:31 abilitytao 閱讀(1317) 評論(0)  編輯 收藏 引用

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