• <ins id="pjuwb"></ins>
    <blockquote id="pjuwb"><pre id="pjuwb"></pre></blockquote>
    <noscript id="pjuwb"></noscript>
          <sup id="pjuwb"><pre id="pjuwb"></pre></sup>
            <dd id="pjuwb"></dd>
            <abbr id="pjuwb"></abbr>
            posts - 74,  comments - 33,  trackbacks - 0
            Balance
            Time Limit: 1000MS Memory Limit: 30000K
            Total Submissions: 1159 Accepted: 553

            Description

            Gigel has a strange "balance" and he wants to poise it. Actually, the device is different from any other ordinary balance.
            It orders two arms of negligible weight and each arm's length is 15. Some hooks are attached to these arms and Gigel wants to hang up some weights from his collection of G weights (1 <= G <= 20) knowing that these weights have distinct values in the range 1..25. Gigel may droop any weight of any hook but he is forced to use all the weights.
            Finally, Gigel managed to balance the device using the experience he gained at the National Olympiad in Informatics. Now he would like to know in how many ways the device can be balanced.

            Knowing the repartition of the hooks and the set of the weights write a program that calculates the number of possibilities to balance the device.
            It is guaranteed that will exist at least one solution for each test case at the evaluation.

            Input

            The input has the following structure:
            ? the first line contains the number C (2 <= C <= 20) and the number G (2 <= G <= 20);
            ? the next line contains C integer numbers (these numbers are also distinct and sorted in ascending order) in the range -15..15 representing the repartition of the hooks; each number represents the position relative to the center of the balance on the X axis (when no weights are attached the device is balanced and lined up to the X axis; the absolute value of the distances represents the distance between the hook and the balance center and the sign of the numbers determines the arm of the balance to which the hook is attached: '-' for the left arm and '+' for the right arm);
            ? on the next line there are G natural, distinct and sorted in ascending order numbers in the range 1..25 representing the weights' values.

            Output

            The output contains the number M representing the number of possibilities to poise the balance.

            Sample Input

            2 4	
            -2 3 
            3 4 5 8
            

            Sample Output

            2

            Source

            Romania OI 2002
            郁悶了,dp不會了 昨天吃晚飯回來就做,到走才知道題目意思看錯了,《岳陽樓記》也不會了
            。。。。。郁悶,代碼很爛,不發了
            posted on 2009-02-20 09:25 KNIGHT 閱讀(270) 評論(0)  編輯 收藏 引用
            <2009年2月>
            25262728293031
            1234567
            891011121314
            15161718192021
            22232425262728
            1234567

            常用鏈接

            留言簿(8)

            隨筆檔案

            文章檔案

            Friends

            OJ

            搜索

            •  

            最新評論

            閱讀排行榜

            評論排行榜

            久久亚洲AV成人无码软件| 青青草原综合久久| 国产欧美久久久精品影院| 久久国产免费直播| 热re99久久精品国产99热| 久久亚洲高清综合| 久久人人爽人人爽人人AV| 精品99久久aaa一级毛片| 久久人人爽人人爽人人片AV不| 久久精品aⅴ无码中文字字幕不卡 久久精品aⅴ无码中文字字幕重口 | 精品久久久噜噜噜久久久 | 精品久久久久久中文字幕| 久久综合综合久久狠狠狠97色88 | 人人狠狠综合久久88成人| 久久精品中文字幕有码| 久久超乳爆乳中文字幕| 免费精品国产日韩热久久| 99久久国产亚洲高清观看2024| 人妻无码αv中文字幕久久琪琪布| 狠狠色综合久久久久尤物| 欧洲精品久久久av无码电影| 亚洲精品tv久久久久久久久久| 国产精品久久影院| 99久久99这里只有免费费精品| 久久这里都是精品| 天天做夜夜做久久做狠狠| 国产91久久综合| 91久久精品国产91性色也| 国产精品久久久久影院嫩草| 久久99精品久久久久久动态图 | 亚洲成色999久久网站| 国产精品无码久久综合| 欧美va久久久噜噜噜久久| 亚洲午夜久久久久妓女影院| 久久久久久精品成人免费图片| 一级a性色生活片久久无少妇一级婬片免费放 | 国产成人综合久久精品尤物| 久久综合九色综合欧美狠狠| 大美女久久久久久j久久| 久久久久亚洲AV综合波多野结衣| 97久久精品人人做人人爽|